(x+1)(x+2)(x+3)(x+6)=3x^2

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Solution for (x+1)(x+2)(x+3)(x+6)=3x^2 equation: 



(x+1)(x+2)(x+3)(x+6)=3x^2

We move all terms to the left:

(x+1)(x+2)(x+3)(x+6)-(3x^2)=0

determiningTheFunctionDomain
-3x^2+(x+1)(x+2)(x+3)(x+6)=0

We multiply parentheses ..

-3x^2+(+x^2+2x+x+2)(x+3)(x+6)=0

We multiply parentheses ..

-3x^2+(+x^2+2x+x+2)(+x^2+6x+3x+18)=0

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